Good morning! Here's our prompt for today.

Write a recursive algorithm that swaps every two nodes in a linked list. This is often called a pairwise swap. For example:

1/*
2original list
31 -> 2 -> 3 -> 4
4
5after swapping every 2 nodes
62 -> 1 -> 4 -> 3
7*/

You may assume that the definition of a linked list node is:

1function Node(val) {
2  this.value = val;
3  this.next = null;
4}

The method will be invoked as such after setup:

1const list = new Node(1);
2list.next = new Node(2);
3list.next.next = new Node(3);
4list.next.next.next = new Node(4);
5
6swapEveryTwo(list);

Constraints

• Length of the linkedlist <= 100000
• The nodes will always contain integer values between -1000000000 and 1000000000
• The list can be empty
• Expected time complexity : O(n)
• Expected space complexity : O(n)

Note: The strength of linked lists is that you can dynamically add or remove any nodes within a constant time, given the address of the node. This is not possible in arrays or a sequential memory holding data structure. Each node in a linked list is created dynamically on the heap section of the memory. For this reason, you can create a very large Linked List (most probably larger than an array of the same size) as long as you have a memory to allocate. Creating more nodes than your memory can store will result in a heap overflow.

Try to solve this here or in Interactive Mode.

How do I practice this challenge?

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    'PASSED: `swap_every_two(list1)` should return `4 -> 5 -> 6 -> 7 -> 8 -> 9 -> 10`'

var assert = require('assert');

​

function swapEveryTwo(head) {

  // Fill in this method

  return head;

}

​

function Node(val) {

  this.val = val;

  this.next = null;

}

​

function LinkedListNode(val) {

  this.val = val;

  this.next = null;

}

​

var list1 = new LinkedListNode(3);

var nodes1 = [4, 5, 6, 7, 8, 9, 10];

createNodes(list1, nodes1);

​

var list2 = new LinkedListNode(1);

var nodes2 = [2, 3, 4, 5, 6, 7, 8];

createNodes(list2, nodes2);

​

function createNodes(head, nodes) {

  for (let i = 0; i < nodes.length; i++) {

    var newNode = new LinkedListNode(nodes[i]);

    head.next = newNode;

We'll now take you through what you need to know.

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