Here is the interview question prompt, presented for reference.
Arrays are amazing for looking up elements at specific indices as all elements in memory are contiguous, allowing for O(1)
or constant time lookups. But often we don't, or can't, perform lookups via indices. Hash maps and hash tables are a way around this, enabling us to lookup via keys
instead.
Can you implement the Map
class from scratch? Only two methods are necessary-- get
and set
. Many programming languages have a built-in hash or dictionary primitive (like Javascript
Object
s and {}
notation), but we don't want to use that for this exercise.
Note: Regular Javascript
objects and the Map
class are both simple key-value hash tables/associative arrays, with a few key differences:
A Map
object can iterate through its elements in insertion order, whereas JavaScript's Object
s don't guarantee order. In addition, Object
s have default keys due to their prototype, and Map
s don't come with default keys. Here's a good breakdown of the two. For the purpose of this exercise, let's assume the same functionality for both.
For the two methods you'll define:
get(key: string)
should be given a key, and return the value for that key.set(key: string, val: string)
should take a key and a value as parameters, and store the pair.Additionally, we've supplied the below hashing function hashStr
. It tries to avoid collision, but is not perfect. It takes in a string value and returns an integer.
function hashStr(str) {
let finalHash = 0;
for (let i = 0; i < str.length; i++) {
const charCode = str.charCodeAt(i);
finalHash += charCode;
}
return finalHash;
}
console.log(hashStr('testKey'))
def hashStr(key):
result = 5381
for char in key:
result = 33 * result + ord(char)
return result
print(hashStr("testKey"))
public class Main {
public static int hashStr(String str) {
int finalHash = 0;
for (int i = 0; i < str.length(); i++) {
char charCode = str.charAt(i);
finalHash += (int) charCode;
}
return finalHash;
}
public static void main(String[] args) {
System.out.println(hashStr("testKey"));
}
}
Let's call our new class the Hashmap
class, and use it like such:
const m = new Hashmap();
m.set('name', 'Jake');
console.log(m.get('name'));
m = Hashmap()
m.set('name', 'Jake')
print(m.get('name'))
import java.util.HashMap;
public class Main {
public static void main(String[] args) {
HashMap<String, String> m = new HashMap<>();
m.put("name", "Jake");
System.out.println(m.get("name"));
}
}
10000
key,value
pair and retrieving a value : O(1)
O(n)
You can see the full challenge with visuals at this link.
Challenges • Asked over 5 years ago by Jake from AlgoDaily
This is the main discussion thread generated for Implement A Hash Map.
Thanks again @mattvanwinkle:disqus, there was a syntax error in one of the tests.
It seems to be working fine now!
I'll be sure to write some automated tests to ensure the rest of the test cases work :-)
In python:
solution of the set part looks wrong, as there is no test case which is going for else so it works.
else:
listatindex = self.storage[index]
if p not in listatindex:
self.storage[index] = [p]
self.size += 1
else:
for i in self.storage[index]:
if i == p:
i.value = val
break
In the Javascript sandbox there is an error in the tests.
The line that says assert.isUndefined creates an error message that it is not a function, and won't trigger the lesson end.
Should be assert.equal(dict.get('jake'), undefined);
... as written at the end in the "our final solution" section.
Thanks Luci, this is fixed!