Here is the interview question prompt, presented for reference.
Let's define the "compacting" of a string as taking an input like the following: 'sstttrrrr'
.
We want to take the number of sequential appearances (number of times it shows up in a row) of each letter:
s: 2
t: 3
r: 4
And denote them next to the original character in the string, getting rid of the duplicates. In our above example, our output is: 's2t3r4'
.
How long is this compacted string? Could you write a method that takes in a string and returns the length of the compacted one? Could you solve it using only O(1) extra space?
Here are few other examples:
compactLength('aabbbbbbbbbbbbb')
// 5 because we end up with `a2b13`
Another to consider:
compactLength('s')
// 1 because we still end up with just `s`
100000
O(n)
O(1)
You can see the full challenge with visuals at this link.
Challenges • Asked almost 7 years ago by Jake from AlgoDaily
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