Good evening! Here's our prompt for today.
In a given array of numbers, one element will show up once and the others will each show up twice. Can you find the number that only appears once in O(n) linear time? Bonus points if you can do it in O(1) space as well.
SNIPPET
1lonelyNumber([4, 4, 6, 1, 3, 1, 3])
2// 6
3
4lonelyNumber([3, 3, 9])
5// 9Constraints
- Length of the array <=
100,000 - The values of the array will be between
-1,000,000,000and1,000,000,000
Try to solve this here or in Interactive Mode.
How do I practice this challenge?
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​def lonely_number(numbers): # fill in return numbers​​import unittest​​class Test(unittest.TestCase): def test_1(self): assert lonely_number([4, 4, 6, 1, 3, 1, 3]) == 6 print("PASSED: `lonely_number([4, 4, 6, 1, 3, 1, 3])` should return `6`")​ def test_2(self): assert lonely_number([3, 3, 9]) == 9 print("PASSED: `lonely_number([3, 3, 9])` should return `9`")​ def test_3(self): assert callable(lonely_number) == True print("PASSED: `lonely_number` is a function")​ def test_4(self): assert lonely_number([3, 3, 9]) == 9 print("PASSED: `lonely_number([1])` should return `1`")​​if __name__ == "__main__": unittest.main(verbosity=2) print("Nice job, 4/4 tests passed!")OUTPUT
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