Good morning! Here's our prompt for today.

A circular array is one where the next element of the last element is the first element.

You know how standard arrays look. Instead of [1, 2, 3, 4], imagine the following, where after index 7, we'd move back to index 0.

Can you write a method nextLargerNumber(nums: array) to print the next immediate larger number for every element in the array?

Note: for any element within the circular array, the next immediate larger number could be found circularly-- past the end and before it. If there is no number greater, return -1.

Take the following example, with an analysis for each index:

1nextLargerNumber([3, 1, 3, 4])
2// [4, 3, 4, -1]
3// 3's next greater is 4
4// 1's next greater is 3
5// 3's next greater is 4 again
6// 4 will look to the beginning, but find nothing, so -1

Constraints

• Length of the array <= 100000
• The array will contain values between -1000000000 and 1000000000
• Expected time complexity : O(n)
• Expected space complexity : O(n)

Try to solve this here or in Interactive Mode.

How do I practice this challenge?

xxxxxxxxxx

var assert = require('assert');

​

function nextLargerNumber(nums) {

  // implement this function

  return nums;

}

​

try {

  assert.deepEqual(nextLargerNumber([3, 1, 3, 4]), [4, 3, 4, -1]);

​

  console.log(

    'PASSED: assert.deepEqual(nextLargerNumber([3, 1, 3, 4]), [4, 3, 4, -1])'

  );

} catch (err) {

  console.log(err);

}

​

Tired of reading? Watch this video explanation!

To change the speed of the video or see it in full screen, click the icons to the right of the progress bar.

We'll now take you through what you need to know.

How do I use this guide?