Step 2/3 Iterate through the rest of the elements in a for-loop.

• Mark the iterated on/current element as the next element.
• If stack is not empty, compare top element of the stack with next.
• If next is greater than the top element, pop the element from the stack. What this means is that we've determined next is the next greater element for the popped number.
• While the popped element is smaller than next, keep popping off the top of the stack. As the logic follows, next becomes the next greater element for all the popped elements.