AlgoDaily - Validate Palindrome

Validate Palindrome (Easy)

Good evening! Here's our prompt for today.

You may see this problem at Microsoft, Amazon, Linkedin, Stripe, Paypal, Yelp, Airbnb, Reddit, Datadog, Rubrik, Gusto, Lucid Software, Digitalocean, Servicenow, Zoom, Intel, and Zoominfo.

Given a string str, can you write a method that will return True if is a palindrome and False if it is not? If you'll recall, a palindrome is defined as "a word, phrase, or sequence that reads the same backward as forward". For now, assume that we will not have input strings that contain special characters or spaces, so the following examples hold:

1str = 'thisisnotapalindrome'
2is_palindrome = is_palindrome(str)
3# False
4
5str = 'racecar'
6is_palindrome = is_palindrome(str)
7# True

For an extra challenge, try to ignore non-alphanumerical characters. The final solution that we present will handle all edge cases.

Constraints

Length of the given string <= 100000
The string will consist of ASCII characters (some or all)
Expected time complexity : O(n)
Expected space complexity : O(1)

xxxxxxxxxx
​
 
def is_palindrome(s):
    # fill in
    return True
​
​
# print(is_palindrome('A Santa Lived As a Devil At NASA'));
​
​
import unittest
​
​
class Test(unittest.TestCase):
    def test_1(self):
        assert is_palindrome("A Santa Lived As a Devil At NASA") == True
        print(
            "PASSED: assert is_palindrome('A Santa Lived As a Devil At NASA') == True"
        )
​
    def test_2(self):
        assert is_palindrome("gold") == False
        print("PASSED: assert is_palindrome('gold') == False")
​
    def test_3(self):
        assert is_palindrome("a") == True
        print("PASSED: assert is_palindrome('a') == True")
​
    def test_4(self):

OUTPUT

Results will appear here.